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RegexDemo.java
Output
Click the below link to download the code:
https://sites.google.com/site/ramj2eev1/home/javabasics/RegexDemo_metachar_dot_cal.zip?attredirects=0&d=1
Github Link:
https://github.com/ramram43210/Java/tree/master/BasicJava/RegexDemo_metachar_dot_cal
Bitbucket Link:
https://bitbucket.org/ramram43210/java/src/57d5e7f2c5fabff367c40b36a92925e1158e7f5a/BasicJava/RegexDemo_metachar_dot_cal/?at=master
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https://www.youtube.com/watch?v=bOl4sDJfeAU&list=UUhwKlOVR041tngjerWxVccw
RegexDemo.java
import java.util.regex.Matcher;
import java.util.regex.Pattern;
/**
* Meta Characters example
*/
public class RegexDemo
{
public static void main(String[] args)
{
/*
* Meta characters affect the way a pattern is matched, in a
* way adding logic to the search pattern. The Java API
* supports several metacharacters, the most straightforward
* being the dot “." which matches any character:
*/
calculateMatches(".", "foofoo");
/*
* Notice the dot after the foo in the regex. The matcher
* matches every text that is preceded by foo since the last
* dot part means any character after. So after finding the
* first foo, the rest is seen as any character. That is why
* there is only a single match.
*/
calculateMatches("foo.", "foofoo");
}
private static void calculateMatches(String regex, String inputText)
{
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(inputText);
int matches = 0;
/*
* The find method keeps advancing through the input text and
* returns true for every match, so we can use it to find the
* match count as well:
*/
while (matcher.find())
{
++matches;
}
System.out.println("Number of Matches = " + matches);
}
}
import java.util.regex.Pattern;
/**
* Meta Characters example
*/
public class RegexDemo
{
public static void main(String[] args)
{
/*
* Meta characters affect the way a pattern is matched, in a
* way adding logic to the search pattern. The Java API
* supports several metacharacters, the most straightforward
* being the dot “." which matches any character:
*/
calculateMatches(".", "foofoo");
/*
* Notice the dot after the foo in the regex. The matcher
* matches every text that is preceded by foo since the last
* dot part means any character after. So after finding the
* first foo, the rest is seen as any character. That is why
* there is only a single match.
*/
calculateMatches("foo.", "foofoo");
}
private static void calculateMatches(String regex, String inputText)
{
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(inputText);
int matches = 0;
/*
* The find method keeps advancing through the input text and
* returns true for every match, so we can use it to find the
* match count as well:
*/
while (matcher.find())
{
++matches;
}
System.out.println("Number of Matches = " + matches);
}
}
Output
Number of Matches = 6
Number of Matches = 1
Number of Matches = 1
Click the below link to download the code:
https://sites.google.com/site/ramj2eev1/home/javabasics/RegexDemo_metachar_dot_cal.zip?attredirects=0&d=1
Github Link:
https://github.com/ramram43210/Java/tree/master/BasicJava/RegexDemo_metachar_dot_cal
Bitbucket Link:
https://bitbucket.org/ramram43210/java/src/57d5e7f2c5fabff367c40b36a92925e1158e7f5a/BasicJava/RegexDemo_metachar_dot_cal/?at=master
See also:
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